Question

It is given that triangle ABC is similar to EDF such that AB=5cm,AC=7cm, DF=15cm and DE=12cm.FIND the length of remaining sides of the traingles.

Answer 1

According to AA criterion,

AB/DE=BC/DF=AC/EF

5/12=BC/15=7/EF

AT FIRST,

5/12=BC/15(CROSS MULTIPLY)

12BC=75

BC=75/12

   =6.25cm

NEXT,

5/12=7/EF(CROSS MULTIPLY)

5EF=84

EF=84/5

    =16.8cm

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Answer 2

Answer:

In triangle ABC/ similar with Triangle DEF

Step-by-step explanation:AB/DE=BC/DF

5/12=BC/15

CROSS MULTIPLICATION

BC=75/12

6.25

Next

5/12=7/EF

EF=84/5

EF=16.8