It is given that triangle ABC = triangle FDE and AB=4cm, Angle B=40° and Angle A=60°. Then which of the following is true:
(A) DE=4cm , angle A=80
(B) DE=4cm , angle C=80
(C)DF=4cm , angle A=80
(D)DF-4cm , angle C=80
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Answer:
D) DF-4cm, angle C= 80
Step-by-step explanation:
Therefore, ∆ ABC is congruent to ∆FDE ...(Given)
Therefore, Side AB is congruent to Side DF (Common side)
Therefore, Angle A + Angle B + Angle C = 180°
60° + 40° + Angle C = 180°
100° + Angle C = 180°
Angle C = 180-100
= 80°
Answer :- D) DF- 4cm, Angle C = 80° is true.
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