Math, asked by ratanatepyn, 4 months ago

It is given that x=12−√3.x=12−3. The value of x7−2√3x6−x5+x3−4x2+2x−√3x7−23x6−x5+x3−4x2+2x−3 is​

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Answered by soniya102saxena41
0

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