It is given that x varies directly with y^2 and x=3 when y =3. Find the value of x when y=45
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Step-by-step explanation:
Given:-
x varies directly with y^2and x=3 when y =3.
To find:-
Find the value of x when y=45
Solution:-
Given that :
x varies directly with y^2
=>x ∝ y^2
=>x / y^2 = k------(1) , where k is a constant.
now , If x = 2 then y = 3
=>k = x/y^2
=>k = 2/3^2
=>k = 2/(3×3)
=>k=2/9
The value of k = 2/9
now,
If y = 45 then from (1)
k= x/y^2
=>x = k ×y^2
=>x = (2/9)×45^2
=>x = (2×45×45)/9
=>x = 2×45×5
=>x = 450
Therefore, x = 450
Answer:-
The value of x for the given problem is 450
Used formula:-
if x varies directly with y then
x ∝ y=>x / y = k, where k is a constant.
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