It is given that ∠XYZ = 64° and XY is produced to point P. Draw a figure from the given information. If ray YQ bisects ∠ZYP, find ∠XYQ and reflex ∠QYP.
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Given,
∠XYZ=64°
YQ bisects ∠ZYP
∠XYZ+∠ZYP=180° (Linear Pair)
⇒64
+∠ZYP=180°
∠ZYP=116°
Also, ∠ZYP=∠ZYQ+∠QYP
∠ZYQ=∠QYP (YQ bisects∠ZYP)
⇒∠ZYP=2∠ZYQ
⇒2∠ZYQ=116°
⇒∠ZYQ=58°
=∠QYP
Now, ∠XYQ=∠XYZ+∠ZYQ
⇒∠XYQ=64°+58°
⇒∠XYQ=122°
Also, reflex ∠QYP=180° +∠XYQ
∠QYP=180 +122
⇒∠QYP=302∘
Answered by
2
Answer:
Given,
∠XYZ=64∘
YQ bisects ∠ZYP
∠XYZ+∠ZYP=180∘(Linear Pair)
⇒64∘+∠ZYP=180∘
∠ZYP=116∘
Also, ∠ZYP=∠ZYQ+∠QYP
∠ZYQ=∠QYP (YQ bisects∠ZYP)
⇒∠ZYP=2∠ZYQ
⇒2∠ZYQ=116∘
⇒∠ZYQ=58∘=∠QYP
Now, ∠XYQ=∠XYZ+∠ZYQ
⇒∠XYQ=64∘+58∘
⇒∠XYQ=122∘
Also, reflex ∠QYP=180∘+∠XYQ
∠QYP=180∘+122∘
⇒∠QYP=302∘
thank you
by
_vaishnavi
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