It is given the ABC congruent FDE and AB=4 cm, angleB = 40' and angle E = 60',
then which of the following is true.
(A) DE=4 cm, ZA=80°
(B) DE = 4 cm, ZC=80°
(C) DF=4 cm, ZA=80°
(D) DF = 4 cm, ZC=80°
Please give me the answer
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Given : ΔABC ≅ Δ FDE
AB = 4cm
∠B = 40°
∠E = 60°
To Find : which is the following is true
(a) DE =4cm ,angle A = 80°
(b) DE=4cm , angle C= 80°
(c) DF=4cm, angle A=80°
(d)DF=4cm,angle C = 80 °
Solution:
ΔABC ≅ Δ FDE
corresponding sides and angles are equal
AB = DF => DF = 4 cm
BC = DE
AC = FE
∠A = ∠F =
∠B = ∠D = 40°
∠C = ∠E = 60°
=> ∠A = ∠F = ( 180° - 40° - 60°) = 80°
Hence correct option is :
(c) DF=4cm, angle A=80°
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