Math, asked by SRKVfc, 1 month ago

It is hard to find please help me.​

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Answered by 12thpáìn
86

Question

AB is a diameter of a circle, centre O. C is a point on the circumference of a circle, such that ∠CAB = 2 x ∠CBA. Find ∠CBA.

Given

  • AB is a diameter.
  • C is a point on the circumference.
  • ∠CAB = 2 x ∠CBA

To Find

  • ∠CBA

Step by step explanation

  • AB is a Diameter.
  • C is a point on the circumference.

 \mathfrak{as \: we \: know \: that}

 \sf \: The ~angle ~at ~the~ circumference~ in~ a~ semicircle~ is~ a~ right ~angle.

∠ACB= 90⁰

Let, ∠CBA=x

then, ∠CAB = 2x

 \sf \: →∠ACB+∠CBA+∠CAB = 180⁰ \:  \:  \:  \:  \:  \pink{angle \: sum \: property}

\sf→90°+3x=180°

\sf→3x=90

~~~~~~~\sf x=30

\sf∠CBA=30⁰

\sf∠CAB = 2×30°

~~~~~~~~~~~\underline{\boxed{\sf{∠CAB = 30°}}}

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