Question

it is impossible to have two numbers whose HCF is 20 and LCM is 630 give reason​

Answer 1

it is not possible to have two numbers whose hcf is 20 and lcm is 630 because hcf of two numbers is always a factor of lcm of those numbers.So it is not possible

Answer 2

L.C.M. is always divisible by H.C.F.

Step-by-step explanation:

Given  : H.C.F. is 20 and L.C.M. is 630

Now as we know

L.C.M. is always divisible by H.C.F.

Therefore

$\dfrac{L.C.M.}{H.C.F.} = \dfrac{630}{20} =\dfrac{63}{2}$

Now in this case  L.C.M. is not divisible by H.C.F.

Hence, It is impossible to have two numbers whose  H.C.F. is 20 and L.C.M. is 630

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