it is it is given that the angle BAD equal to the angle C A and Angle B equal to the angle D prove that the angle ADB equal to angle AEC
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ABC is an isosceles triangle with AB =AC and D is a point on BC such that AD⊥BC (Fig. 7.13). To prove that ∠BAD=∠CAD, a student proceeded as follows:
ΔABD and ΔACD,
AB = AC (Given)
∠B=∠C (because AB = AC)
and ∠ADB=∠ADC
Therefore, ΔABD≅ΔACD(AAS)
So, ∠BAD=∠CAD(CPCT)
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