Question

it is khadija's birthday today. one year from now she will be the twice as old as she was 10 year before .what is her present age

Answer 1

Answer:

let the present age of Khadija is x .

one year from now x +1

before 10 years x-10

x+1= 2(x-10)

by using this equation u can find the value of x.

I think this will help.

Answer 2

Answer:

let her age be x

after 1 year her age will be x+1=2(x-10)

x+1=2x-20

1+20=2x-x

x=21 years