It is known that a box of 550 electric blubs cointain 22 defective bulb. One bulb is taken out at random out of box . Find the probability of getting i) a defective bulb i) a good bulb
Answers
Answered by
59
Hi there !!
Total number of bulbs = 550
No: of defective bulbs = 22
No: of bulbs that are not defective = 550 - 22 = 528
i)
Probability of a defective bulb = No: of defective bulbs / Total number of bulbs
= 22/550
= 2 / 50
= 1/25
ii)Probability of a bulb that is not defective = No: of bulbs that are not defective / Total number of bulbs
= 528 / 550
Total number of bulbs = 550
No: of defective bulbs = 22
No: of bulbs that are not defective = 550 - 22 = 528
i)
Probability of a defective bulb = No: of defective bulbs / Total number of bulbs
= 22/550
= 2 / 50
= 1/25
ii)Probability of a bulb that is not defective = No: of bulbs that are not defective / Total number of bulbs
= 528 / 550
Answered by
17
Hi friend
____________
Total Electric bulbs = 550
defective bulbs = 22
Good bulbs = 550-22
=528
_____________________________________________________________
Probability of that the bulb is damaged = 22/550
= 1/25
Probability that the bulb is good = 1- 1/25
= 24 /25
____________
Total Electric bulbs = 550
defective bulbs = 22
Good bulbs = 550-22
=528
_____________________________________________________________
Probability of that the bulb is damaged = 22/550
= 1/25
Probability that the bulb is good = 1- 1/25
= 24 /25
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