It is known that a box of 550 electric blubs cointain 25 defective bulb. One bulb is taken out at random out of box . Find the probability of getting i) a defective bulb i) a good bulb
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Total number of bulbs = 550
Number of defective bulbs = 25
Number of good bulbs = 550 - 25 = 525
i) Probability that a bulb is defective = 25/550 = 1/22
ii) Probability that a bulb is good = 525/550 = 21/22
Hope This Helps You!
Number of defective bulbs = 25
Number of good bulbs = 550 - 25 = 525
i) Probability that a bulb is defective = 25/550 = 1/22
ii) Probability that a bulb is good = 525/550 = 21/22
Hope This Helps You!
anilkumar78ak90:
Your ans is wrong
When we divide 525/550 ans is 3/22 ok
oh when we divide the answer is 3/22 instead of 21/22
I think u should Check yours answer in claculator
your answer is 1000000% wrong
when we divide 525 by 550 the answer will be 21/ 22
Please please try to cut both the numenetor and denomenetor with 25
Answered by
4
Given it is known that a box of 550 bulbs contains 25 defective bulb.
Therefore from 550 bulb ,
No. of good bulbs= 550 - 25 = 525
Let E1 be event of getting defective bulb
Favourable outcome = 25
Total no. of outcomes = 550
P (E1) = 25/550=1/22
Let E2 be event of getting good bulbs
Favourable outcomes= 525
P (E2)= 525/550=21/22
Therefore from 550 bulb ,
No. of good bulbs= 550 - 25 = 525
Let E1 be event of getting defective bulb
Favourable outcome = 25
Total no. of outcomes = 550
P (E1) = 25/550=1/22
Let E2 be event of getting good bulbs
Favourable outcomes= 525
P (E2)= 525/550=21/22
Your ans is wrong
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