Question

It is known that a box of 550 Electric bulbs contains 22 faulty bulbs One bulb is taken out at random out of the box find the probability of getting a faulty bulb and good bulb

Answer 1

No. of faulty bulbs = 22
Total no. of bulbs = 550

P(Faulty bulb) = no. of faulty bulbs/Total no. of bulbs

P(faulty bulb) = 22/550

P(good bulb) = 1 - P(faulty bulb)

P(good bulb) = 1 - 22/550 = 528/550

Hope this will helpsss.......

Answer 2

1)getting fault bulb

E(n)=22
E(s)=550
P=E(n)/E(s)
P=22/550
P=0.04

2)getting good bulb
E(n)=550-22
=528
E(s)=550
P=528/550
P=0.96

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