Question

it is my last question please solve it​

Answer 1

Answer:

10, 2^12, 4/9

Step-by-step explanation:

$289=17^2$

$x/5=2$

∴$x=10$

$16^\frac{1}{2} =4$

Thus, $4^3\div 4^-^3=m$.

∴$m=4^6=2^1^2$

Let $t=\frac{2}{3}$.

$t^-^7\div t^-^1^0\times t^-^5$

$=t^-^2$

∴$\frac{2^2}{3^2} =\frac{4}{9}$