Question

It is needed to seat 5 boys and 4 girls in a row so that the girl gets the even places. How many such arrangements are possible?​

Answer 1

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$\Large\fbox{\color{purple}{QUESTION}}$

It is needed to seat 5 boys and 4 girls in a row so that the girl gets the even places. How many such arrangements are possible?

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$\Large\fbox{\color{purple}{ SOLUTION }}$

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➡️5 boys and 4 girls are to be seated in a row so that the girl gets the even places.

➡️The 5 boys can be seated in 5! Ways.

➡️For each of the arrangement, the 4 girls can be seated only at the places which are cross marked to make girls occupy the even places).

For each of the arrangement, the 4 girls can be seated only at the places which are cross marked to make girls occupy the even places).B x B x B x B x B

➡️So, the girls can be seated in 4! Ways.

➡️Hence, the possible number of arrangements

➡️= 4! × 5! = 24 × 120 = 2880

$\Large\mathcal\green{FOLLOW \: ME}$

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Answer 2

Answer:

➡ SOLUTION:-

⭐ GIVEN ⭐

➡️5 boys and 4 girls are to be seated in a row so that the girl gets the even places.

➡️The 5 boys can be seated in 5! Ways.

➡️For each of the arrangement, the 4 girls can be seated only at the places which are cross marked to make girls occupy the even places).

For each of the arrangement, the 4 girls can be seated only at the places which are cross marked to make girls occupy the even places).B x B x B x B x B

➡️So, the girls can be seated in 4! Ways.

➡️Hence, the possible number of arrangements

➡️= 4! × 5! = 24 × 120 = 2880✔✔

Step-by-step explanation:

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