English, asked by harshitha182490, 10 months ago

) It is observed that the pipe A can fill the tank in 15 hrs and the same tank is filled by pipe B in 20 hrs. The third pipe C can vacant the tank in 25 hrs. If all the pipes get opened initially and after 10 hrs, the pipe C is closed, then how long will it take to fill the tank? *
1 point

Answers

Answered by FelisFelis

Answer:

The total time taken is 12 hours

Explanation:

Consider the provided information.

Let the capacity of tank is 300 liter

It is given that A can fill the tank in 15 hrs.

That means A can fill 20 liter water in 1 hour (300/15=20)

It is given that B can fill the tank in 20 hrs.

That means B can fill 15 liter water in 1 hour (300/20=15)

It is given that C can vacant the tank in 25 hrs.

That means C can vacant 12 liter water in 1 hour (300/25=12)

If they all open at the same time then:

20+15-12=23 liter

If all the pipes get opened initially that means they are filling 23 liter water per hour.

After 10 hours they will fill the tank: 23×10=230 liter

Now we need to fill only 70 liter of water in order to fill the tank completely.

(300-230=70)

After 10 hours Pipe C is closed so the total water we can fill is: 15+20=35

Therefore, it required 2 hours to fill remaining 70 liters of water: $\frac{70}{35} =2$

Hence, the total time taken is 10 hours + 2 hours = 12 hours

Answered by tanyaprasad9999