it is of ratio proportion
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Given,
a= 4√6(√2+√3)
Using Componendo and dividendo rule the expression can be rewritten as,
{(a+2√2+a-2√2)/a+2√2-a+2√2)}+{(
a+2√3+a-2√3)/a+2√3-a+2√3)}
{2a/4√2}+{2a/4√3}
Taking LCM as √6 we get,
(2√3a+2√2a)/4√6
2a(√3+√2)/4√6
a(√3+√2)/2√6
{(4√6)(√3+√2)}/{(√3+√2)(2√6)}
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I hope it will help you
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