Question

it is physics question a ball thrown upward takes 4 second to reach the maximum height find the maximum height

Answer 1

Intial Velocity (u)= x m/s
Final Velocity at maximum height (v)=0m/s
Accerlation due to gravity(a)=-10 m/s
As ball thrown against gravity take
=- accerlation
Time(t)=4 seconds
Using v=u+at
0=x+(-10×4)
0=x-40
x=40
Intial Velocity =40 m/s

Now,Intial Velocity (u)=40 m/s
Final Velocity at maximum height(v)=0m/s
Accerlation due to gravity(a)=-10 m/s
Time (t)=4 seconds
Maximum height it reach(s)=???

Using,v²=u²+2as
=0²=40²+2×(-10)×s
0=1600-20s
20s=1600
s=1600/20
s=80

Maximum Height ball reach=80 metres