Question

It is possible to construct a rectangle with Perimeter 20 cm and the ratio of length and breadth as 3:2? Also, justify it with the help of construction​

Answer 1

Step-by-step explanation:

Let the length be l m and the breadth be b m.

Then the area would be lb=400

Perimeter would be 2(l+b)=80 

lb=400

⇒2(l+b)=80

⇒l+b=40

∴b=40−l --(1)

Substituting (1) in Area, we get

⇒l(40−l)=400

⇒40l−l2=400

⇒l2−40l+400=0

⇒(l−20)(l−20)=0

∴l=20

has equal roots, so it is possible to design the rectangle of given parameters. 

⇒b=40−20=20

We now know that the length of the park is 20 m and the breadth of the park is also 20 m.

Answer 2

Answer:

MARK AS BRAKNLIEST

Step-by-step explanation:

perimeter = 20

2(l +b) = 20

2(2k +3k) =20 [l:b = 2:3]

5k=10

k=2

so l=2k = 4

and b = 3k = 6.

The rectangle has the following properties:

All the properties of a parallelogram apply (the ones that matter here are parallel sides, opposite sides are congruent, and diagonals bisect each other).

All angles are right angles by definition.

The diagonals are congruent.

The properties of rectangle are satisfied here,so rectangle can be formed.