Question

It is related to polynomials topic.

Answer 1

given

x + 1 = 0

x = -1

puting vlaue of x in equation given

x ^3 - x ^2 - (3 -√3) x + √3 = 0

(-1)^3 - ( -1)^2 - (3- √3 ) ( -1 + √3) = 0

-1 -1 - (3 + √3) ( -1 + √3) = 0

solving brackets

-1 -1 + 3 - 3√3 - √3 + 3 = 0

-2 + 9 - 4√3 = 0

7 - 4√3 = 0

so , x + 1 is not a factor of given equation