Math, asked by harshita7748, 1 year ago

It is required surface area of a right circular cylinder of height 14cm is 88cm2..... Find the diameter of the base of the cylinder.....​

Answers

Answered by lovewithsomeone
2

Height (h) of cylinder = 14 cm

Let the diameter of the cylinder be d.

Curved surface area of cylinder = 88 cm2

⇒ 2πrh = 88 cm2 (r is the radius of the base of the cylinder)

⇒ πdh = 88 cm2 (d = 2r)

⇒ d = 2 cm

Therefore, the diameter of the base of the cylinder is 2 cm.

Read more on Brainly.in - https://brainly.in/question/2583805#readmoreHeight (h) of cylinder = 14 cm

Let the diameter of the cylinder be d.

Curved surface area of cylinder = 88 cm2

⇒ 2πrh = 88 cm2 (r is the radius of the base of the cylinder)

⇒ πdh = 88 cm2 (d = 2r)

⇒ d = 2 cm

Therefore, the diameter of the base of the cylinder is 2 cm.

Answered by gopu143
2

hey mate here is the solution of your qun

=} Height (h) = 14cm

Let the diameter of cylinder be d.

Curved Surface Area = 88cm square

2πrh = 88 cm square

π dh = 88 cm square. (d = 2r)

22/7 × d × 14 = 88 cm

d = 2 cm .

hope it helps u

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