Question

. It is required to increase the velocity of a car of
mass 800 kg from 10 m s' to 25 m s' in two
seconds. Calculate the force required.
​

Answer 1

Explanation:

Answer:-

Given that:-

• Mass - 800 kg
• From 10 m/s to 25 m/s
• Time interval of 2 seconds.

Concept:

1. Relation between Acceleration, Initial and Final velocity, and time.
2. Relation of Force, acceleration and mass.

Let's Do!

$\boxed{\bf{Acceleration = \dfrac{Final \ Velocity - Initial \ Velocity}{Time}}}$

$\longrightarrow$ Extend

• Here, Final velocity is 25 m/s
• Here, Initial velocity is 10 m/s
• Here, time is 2 seconds

$\bf{Acceleration = \dfrac{25 - 10}{2}}$

$\boxed{\bf{Acceleration = \dfrac{15}{2}}}$

So, acceleration is 15/2 m/s².

Now, we need to calculate the force.

$\boxed{\bf{Force = Mass \times Acceleration}}$

$\longrightarrow$ Extend

• Here mass is 800 Kg
• Here acceleration is $\dfrac{15}{2}$ m/s².

$\bf{Force = 800 \times \dfrac{15}{2}}$

$\bf{Force = 400 \times 15}$

$\boxed{\bf{Force = 6000 \ N}}$

So, the final answer is 6000 Newton.

[A special vigil on the Units.]

Full formula is not visible? Extend $\longrightarrow$ this side.

Answer 2

Answer:

Here is your answer

Explanation:

Given :

m=80 kg

u=5 m÷s

v=25

m÷s

t=2 s

Formula - v = u + at

=a=10

m÷s^2

Force requires

F = MA = 80× 10 = 800 N

Do this question in the way which I have given. But not the same becz which I have given the example or steps to do this sum

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