It is required to put 6 black balls and 8 green balls in two bags such that neither of the bag is empty. How must the balls be divided so as to give a man
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there are two bags,
so therefore,the no of balls should be divided by 2
black balls =6÷2=3
green balls=8÷2=4
3 black balls and 4, green balls should be there in each bag
I hope it helps!!!
so therefore,the no of balls should be divided by 2
black balls =6÷2=3
green balls=8÷2=4
3 black balls and 4, green balls should be there in each bag
I hope it helps!!!
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