It is required to throw an image, magnified two times, on a screen placed at distance of 6 cm from the object. Find the focal length and nature of the lens
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Answered by
21
Answer
m=2
m=v/u=2
v=2u
also
v=u+6
2u=u+6
u=6
v=2u
v=12
the object distance is always negative
so
u=-6
also the image is on the same side of the object .
so
v=-12
using lens formula
1/f=1/v-1/u
1/f=1/-12-1/-6
1/f=1/12
f=12
Focal length is positive.
So,it is a convex lens.
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Answered by
4
Explanation:
m=2
m=v/u=2
v=2u
also
v=u+6
2u=u+6
u=6
v=2u
v=12
the object distance is always negative
so
u=-6
also the image is on the same side of the object .
so
v=-12
using lens formula
1/f=1/v-1/u
1/f=1/-12-1/-6
1/f=1/12
f=12
Focal length is positive.
So,it is a convex lens.
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