it is right to say that cos(A+B)=cosA+cosB Justify your answer
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No.
cos(A+B) ≠ cosA + cosB
PROOF :
• let A = 0° and B = 90°
now,
cos( A + B ) = cos( 0° + 90° )
= cos(90°)
• cos( A + B ) = 0_________(1)
again,
cosA + cosB = cos0° + cos90°
= 1 + 0
• cosA + cosB = 1_________(2)
from (1) & (2)
cos(A+B) ≠ cosA + cosB
cos(A+B) ≠ cosA + cosB
PROOF :
• let A = 0° and B = 90°
now,
cos( A + B ) = cos( 0° + 90° )
= cos(90°)
• cos( A + B ) = 0_________(1)
again,
cosA + cosB = cos0° + cos90°
= 1 + 0
• cosA + cosB = 1_________(2)
from (1) & (2)
cos(A+B) ≠ cosA + cosB
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