it is the question of number system.
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a²= 3/4
Applying (a+b) ²
{root over(1+a) + root over(1-a)}²
=(1+a) +2[root over{(1+a)(1-a)] +(1-a)
=2 + 2[root over(1- a²) as a²-b²= (a+b) (a-b)
=2 + 2[root over(1- 3/4)]
=2 + 2[root over(1/4)]
=2 + 2x 1/2
=2 + 1
= 3
Applying (a+b) ²
{root over(1+a) + root over(1-a)}²
=(1+a) +2[root over{(1+a)(1-a)] +(1-a)
=2 + 2[root over(1- a²) as a²-b²= (a+b) (a-b)
=2 + 2[root over(1- 3/4)]
=2 + 2[root over(1/4)]
=2 + 2x 1/2
=2 + 1
= 3
allie3:
thanks
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