Question

It is urgent.
If the position vector of a body performing rectilinear motion is given by r = 3tr^2i^+4t^2j^ is m. find the instantaneous at t =1 sec. ​

Answer 1

Answer:

ANSWER

r=(t2−4t+6)i^+(t2)j^

velocity =dtdr=(2t−4)i^+(2t)j^

acceleration =dtdv=(2)i^+(2)j^

a.v=((2t−4)i^+(2t)j^).((2)i^+(2)j^)

when they are perpendicular then a.v = 0 

((2t−4)i^+(2t)j^).((2)i^+(2)j^)=0

(2t−4)×2+4t=0

4t−8+4t=0

t=1s

Answer 2

Answer:

Don't know the answer of the questions