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hey mate here is your answer
Given that area of cuboid = 160cm2
Level of water increased in vessel = 2cm
volume of water = 160 × 2cm3.............(1)
volume of each sphere = 4/3πr3
total volume of 3 sphere = 3 × 4/3 πr3.......... (2)
Given that area of cuboid = 160cm2
Level of water increased in vessel = 2cm
Equating (1) and (2)
(Volumes are equal V1 = V2)
160 × 2 = 3 × 4/3πr3
r3 = 160 × 3 / 3 × 4/3π
r3 = 320 / 4π
r = 2.94cm
=> radius of sphere = 2.94cm
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