Question

it is urgent


Projectile is a particle which is projected into air with an initial velocity against gravity.

A. What is the angle of projection for maximum horizontal range?

B. Obtain the expression for time of flight.

C. An insect is moving in a circle with uniform speed. Obtain the expression for centripetal acceleration (ac) in terms of angular speed (ω)​

Answer 1

Answer:

The time of flight of an object, given the initial launch angle and initial velocity is found with: T=2visinθg T = 2 v i sin ⁡ . The angle of reach is the angle the object must be launched at in order to achieve a specific distance: θ=12sin−1(gdv2) θ = 1 2 sin − 1 ⁡ ( gd v 2 ) .

Answer 2

A. For the maximum range value of sin2A most be maximum
We know maximum value of sin2A is 1
So sin2A is equal to sin90
Therefore the value of A becomes 45
Hence angle of projection for maximum horizontal range is 45 degrees