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Solve These problems
Any 2
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ʜʏ ᴅᴇᴀʀ ʜᴇʀᴇ ɪs ʏᴏᴜʀ ᴀɴsᴡᴇʀ
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1st. Y= 180°-70°= 110°
X= 180°- (30°+ 110°)
= 180°- 140°= 40°
2nd. One of angels of a triangle is 80°
Other angels are equal..
So other angels are,
180°-80°= 100°
=> 100°/ 2= 50°
Hope it may help you..
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1st. Y= 180°-70°= 110°
X= 180°- (30°+ 110°)
= 180°- 140°= 40°
2nd. One of angels of a triangle is 80°
Other angels are equal..
So other angels are,
180°-80°= 100°
=> 100°/ 2= 50°
Hope it may help you..
akhlaka:
Nice answer sisso...
Answered by
1
Hey friend! Here is your answer.
5. y + 70= 180 ( angles drawn on a straight line)
y = 180 - 70
= 110°
Sum of angles of a triangle is 180°
x+ y+ 30= 180
x+110+ 30= 180
x+ 140=180
x=40°
6. Let each of the other two angles be x.
80 + x + x = 180( Sum of angles in a triangle is 180)
80 + 2x = 180
2x = 100
x = 50°
The other two angles measure 50° each
5. y + 70= 180 ( angles drawn on a straight line)
y = 180 - 70
= 110°
Sum of angles of a triangle is 180°
x+ y+ 30= 180
x+110+ 30= 180
x+ 140=180
x=40°
6. Let each of the other two angles be x.
80 + x + x = 180( Sum of angles in a triangle is 180)
80 + 2x = 180
2x = 100
x = 50°
The other two angles measure 50° each
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