Math, asked by Kogami9852, 9 months ago

It p(E)=0.546, what is the probability of 'not E' ?

Answers

Answered by ihrishi
4

Step-by-step explanation:

 \because \: p(E) + \: p( \bar E)  = 1 \\  \\  \therefore \: p( \bar E)  = 1  - p(E) \\  \\ \therefore \: p( \bar E)  = 1  -0.546 \\  \\  \huge \:  \purple{ \boxed{\therefore \: p( \bar E)  =0.454 }}\\ \\Where\: p( \bar E)  \: mean \: 'not\: E' \\\\

Answered by LiarHeart
1

Step-by-step explanation:

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