Question

IT P, Q, R, and S are distinct two digit numbers divisible by 7 then the maximum value of PxQ - R«S is:​

Answer 1

Answer:

8624

Step-by-step explanation:

For getting the maximum value of this question p x q should have the maximum value possible while r x s should have the minimum value possible. you are given that all these numbers are divisible by 7 so largest two digit numbers divisible by 7 are 91 and 98. The least 2 digit numbers divisible by 7 are 14 and 21. the four we have to do like 91 X 98 - 14 x 21 which gives the answer 8624.

Thank you. hope it was helpful

Answer 2

Given : P, Q, R, and S are distinct two digit numbers divisible by 7

To Find : maximum value of P*Q - R * S

Solution:

two digit numbers divisible by 7

14 , 21 , 28 , 35 , 42 , 49 , 56 , 63 , 70  , 77 , 84 , 91 , 98

maximum value of P*Q - R * S

if P and Q are largest  and  R & S are smallest

so P & Q can be  91 and 98

R & S can be  14 and 21

P*Q - R * S  = 91 * 98  -  14  * 21

= 7 * 7( 13 * 14  -  2 * 3)

= 49 ( 182 - 6)

= 49 ( 176)

= 8624

Hence maximum value of P*Q - R * S is 8624

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