Question

It P(x)= X power 4 +1, then find P(2) - P(-2)​

Answer 1

Step-by-step explanation:

Step-by-step explanation:Value of p(2) and p(-2) is 0.

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Given

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)p(2)=2^4+1=16+1=17p(2)=2

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)p(2)=2^4+1=16+1=17p(2)=2 4

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)p(2)=2^4+1=16+1=17p(2)=2 4 +1=16+1=17

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)p(2)=2^4+1=16+1=17p(2)=2 4 +1=16+1=17p(-2)=(-2)^4+1=16+1=17p(−2)=(−2)

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)p(2)=2^4+1=16+1=17p(2)=2 4 +1=16+1=17p(-2)=(-2)^4+1=16+1=17p(−2)=(−2) 4

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)p(2)=2^4+1=16+1=17p(2)=2 4 +1=16+1=17p(-2)=(-2)^4+1=16+1=17p(−2)=(−2) 4 +1=16+1=17

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)p(2)=2^4+1=16+1=17p(2)=2 4 +1=16+1=17p(-2)=(-2)^4+1=16+1=17p(−2)=(−2) 4 +1=16+1=17As the given function is even value of p(2) and p(-2) is same

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)p(2)=2^4+1=16+1=17p(2)=2 4 +1=16+1=17p(-2)=(-2)^4+1=16+1=17p(−2)=(−2) 4 +1=16+1=17As the given function is even value of p(2) and p(-2) is samegives

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)p(2)=2^4+1=16+1=17p(2)=2 4 +1=16+1=17p(-2)=(-2)^4+1=16+1=17p(−2)=(−2) 4 +1=16+1=17As the given function is even value of p(2) and p(-2) is samegivesp(2)-p(-2)=17-17=0

Step-by-step explanation:Value of p(2) and p(-2) is 0. Step-by-step explanation:Givenp(x)=x^4+1p(x)=x 4 +1we have to find the value of p(2)-p(-2)p(2)=2^4+1=16+1=17p(2)=2 4 +1=16+1=17p(-2)=(-2)^4+1=16+1=17p(−2)=(−2) 4 +1=16+1=17As the given function is even value of p(2) and p(-2) is samegivesp(2)-p(-2)=17-17=0Hence, value of p(2) and p(-2) is 0.

Answer 2

Step-by-step explanation:

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