Question

It requires 40ml of 0.5 M Ce4+ to titrate 10ml of 1M Sn2+ to Sn4+. The oxidation state of cerium in the reduced product is:

Answer 1

Final Answer :
The reduced oxidation state of Cerium in the reduced product is Ce3+.

Understanding :
1) Law of equivalents.
n -factor of Sn2+ = 4-2 = 2
x - change in Oxidation state of Ce4+
No. of equivalents of Ce(4+) = No. of equivalents of Sn(2+)
=> 40 * 0.5 * x = 10 * 2 * 1
=> x = 1 .

Therefore, oxidation state of Ce4+ is reduced by 1 unit I. e Ce(3+) .