Question

it's 10 class ques.solve plzz​

Answer 1

Let, total number of observations be n.

Mean wrongly calculated as 50; so sum of all observations wrongly calculated was (50*n).

Now, sum of all observations correctly calculated will be [(50*n) + 110 - 100]

= [(50*n) + 10]

Therefore, mean correctly calculated will be [{(50*n) + 10} / n] = [50 + (10 / n)].

Since, the total number of observations (n) remains unchanged in both cases: so, the value of median too remains unchanged in both cases; and it remains 52 only.

Answer 2

for mean formula is

sum of observations/total no. of observations let the sum of observations be x

ATQ,

x/100=50

therefore x=5000

for true mean =5010 sum of all obersvation because 10 has been increased so true mean 5010/100=

50.1 answer