(it's an Imp que) show that the points A (7,10)B (-2,5)&C (-1,3)are the vertices of an isosceles right ttiangle
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AB=√ [(7-(-2))^2+(10-5)^2]=√[9^2+5^2]=√(81+25)=√106
BC= √[(-2-(-1))²+(5-3)²]=√(1+4)= √5
AC= √[(7-(-1))²+(10-3)²=√(64+49= √113
not isosceles triangle
not right angled
BC= √[(-2-(-1))²+(5-3)²]=√(1+4)= √5
AC= √[(7-(-1))²+(10-3)²=√(64+49= √113
not isosceles triangle
not right angled
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