Math, asked by durgaieeswarin, 7 hours ago

it's in the chapter trigonometry and transformation.
solve the problem and explain I need the correct answer.if so I will mark as brainlist

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Answers

Answered by itzHappyBandiXx
1

Answer:

A and B are partners in a firm sharing profits and losses in the ratio of 3 : 2. A new partner C is admitted. A surrenders 1/15th share of his profit in favour of C and B surrenders 2/15th of his share in favour of C. What is there new ratio and explain how?A and B are partners in a firm sharing profits and losses in the ratio of 3 : 2. A new partner C is admitted. A surrenders 1/15th share of his profit in favour of C and B surrenders 2/15th of his share in favour of C. What is there new ratio and explain how?A and B are partners in a firm sharing profits and losses in the ratio of 3 : 2. A new partner C is admitted. A surrenders 1/15th share of his profit in favour of C and B surrenders 2/15th of his share in favour of C. What is there new ratio and explain how?A and B are partners in a firm sharing profits and losses in the ratio of 3 : 2. A new partner C is admitted. A surrenders 1/15th share of his profit in favour of C and B surrenders 2/15th of his share in favour of C. What is there new ratio and explain how?

Answered by ushmi2006
0

Answer:

∠DAB=∠CBA

Construction :- Produce AB to E and draw CE∥DA,MO∥AB

Proof: So AECD is a parallelogram.

In △BEC

BC=CE (AD=BC=CE,opposite sides of parallelogram)

∠CBE=∠CEB (opposite to equal sides) ---- (1)

∠ADC=∠BEC (opposite angle of a parallelogram) ----- (2)

∠DAB+∠ADC=180

(sum of co-interior angles) ------ (3)

∠ABC+∠EBC=180

(L.P.P.)

∠ABC+∠ADC=180

---- (4) from (2)

From equation (3) and (4)

∠DAB=∠CBA

(ii) ∠BCD=∠EBC ---- (5) (alternate interior angles)

From equations (1),(2), and (5),

∠ADC=∠BCD proved

(iii) In △ABD and ΔBAC

∠BAD=∠ABC

AB=AB (common)

AD=BC (Given)

△ABD≅△BAC (by SAS rule)

BD=AC (By C.P.C.T)

(iv) In △ABD

MO∥AB

MD

AM

=

OD

BO

--- A, (by lemma of B.P.T)

In △ADC

MO∥DC

MD

AM

=

OC

AO

---- B (by B.P.T.)

From equations A and B,

OD

BO

=

OC

AO

---- C

OD

BO

+1=

OC

AO

+1

OD

BO+DO

=

OC

AO+OC

OD

BD

=

OC

AC

OD=OC (AC=BD)

From equation C,

OB=OA (OD=OC)

please mark as brainliest

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