it's in the chapter trigonometry and transformation.
solve the problem and explain I need the correct answer.if so I will mark as brainlist
Answers
Answer:
A and B are partners in a firm sharing profits and losses in the ratio of 3 : 2. A new partner C is admitted. A surrenders 1/15th share of his profit in favour of C and B surrenders 2/15th of his share in favour of C. What is there new ratio and explain how?A and B are partners in a firm sharing profits and losses in the ratio of 3 : 2. A new partner C is admitted. A surrenders 1/15th share of his profit in favour of C and B surrenders 2/15th of his share in favour of C. What is there new ratio and explain how?A and B are partners in a firm sharing profits and losses in the ratio of 3 : 2. A new partner C is admitted. A surrenders 1/15th share of his profit in favour of C and B surrenders 2/15th of his share in favour of C. What is there new ratio and explain how?A and B are partners in a firm sharing profits and losses in the ratio of 3 : 2. A new partner C is admitted. A surrenders 1/15th share of his profit in favour of C and B surrenders 2/15th of his share in favour of C. What is there new ratio and explain how?
Answer:
∠DAB=∠CBA
Construction :- Produce AB to E and draw CE∥DA,MO∥AB
Proof: So AECD is a parallelogram.
In △BEC
BC=CE (AD=BC=CE,opposite sides of parallelogram)
∠CBE=∠CEB (opposite to equal sides) ---- (1)
∠ADC=∠BEC (opposite angle of a parallelogram) ----- (2)
∠DAB+∠ADC=180
∘
(sum of co-interior angles) ------ (3)
∠ABC+∠EBC=180
∘
(L.P.P.)
∠ABC+∠ADC=180
∘
---- (4) from (2)
From equation (3) and (4)
∠DAB=∠CBA
(ii) ∠BCD=∠EBC ---- (5) (alternate interior angles)
From equations (1),(2), and (5),
∠ADC=∠BCD proved
(iii) In △ABD and ΔBAC
∠BAD=∠ABC
AB=AB (common)
AD=BC (Given)
△ABD≅△BAC (by SAS rule)
BD=AC (By C.P.C.T)
(iv) In △ABD
MO∥AB
MD
AM
=
OD
BO
--- A, (by lemma of B.P.T)
In △ADC
MO∥DC
MD
AM
=
OC
AO
---- B (by B.P.T.)
From equations A and B,
OD
BO
=
OC
AO
---- C
OD
BO
+1=
OC
AO
+1
OD
BO+DO
=
OC
AO+OC
OD
BD
=
OC
AC
OD=OC (AC=BD)
From equation C,
OB=OA (OD=OC)
please mark as brainliest