Math, asked by pranjaljoshitws13027, 11 hours ago

it's indices please do slove it​

Attachments:

Answers

Answered by Swarit127
1

Answer:

 {5}^{0}  \times  {4}^{ - 1}  +  {8}^{ \frac{1}{3} }  \\  = 1  \times  {( {2}^{2} })^{ - 1}  +  {( {2}^{3} )}^{ \frac{1}{3} }  \\  = 1 \times  {2}^{2 \times  - 1}  +  {2}^{3 \times  \frac{1}{3} }  \\  = 1 \times  {2}^{ - 2}  +  {2}^{1}  \\  =   \frac{1}{ {2}^{ 2} }  + 2 \\   = \frac{1}{4}  + 2 \\  =  \frac{1 + 8}{4}  \\  =  \frac{9}{4}  \: or \:   { (\frac{3}{2}) }^{2}

Hope it helps you:)

Please mark as brainliest and follow:(

Similar questions