Question

it's indices please do slove it​

Answer 1

Answer:

${5}^{0} \times {4}^{ - 1} + {8}^{ \frac{1}{3} } \\ = 1 \times {( {2}^{2} })^{ - 1} + {( {2}^{3} )}^{ \frac{1}{3} } \\ = 1 \times {2}^{2 \times - 1} + {2}^{3 \times \frac{1}{3} } \\ = 1 \times {2}^{ - 2} + {2}^{1} \\ = \frac{1}{ {2}^{ 2} } + 2 \\ = \frac{1}{4} + 2 \\ = \frac{1 + 8}{4} \\ = \frac{9}{4} \: or \: { (\frac{3}{2}) }^{2}$

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