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A metre rule is balanced 0cm mark. Find the weight of the rule if 20gf is hung from one end.
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Let the weight of the half metre rule be x gf and it acts at the 25 cm mark (centre of gravity).
Now,
•Acticlockwise moment = x * 4
•Clockwise moment = 20 * 21
In equilibrium,
Anticlockwise moment = Clockwise moment
•4x = 20*21
x = 105 gf.
Thus, the weight of the metre rule is 105 gf.
•We know, one gf is the force acting on the body of mass 1 grams, thus mass of the body is 105 grams.
Now,
•Acticlockwise moment = x * 4
•Clockwise moment = 20 * 21
In equilibrium,
Anticlockwise moment = Clockwise moment
•4x = 20*21
x = 105 gf.
Thus, the weight of the metre rule is 105 gf.
•We know, one gf is the force acting on the body of mass 1 grams, thus mass of the body is 105 grams.
CrazyHater29:
Hi thanks
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