Question

It's of chapter trigonometry. Class 10.answer fast plzz​

Answer 1

Step-by-step explanation:

Using Pythagoras theorem ,

AB ^2 =(b/3)^2+b^2=10b^2/9

→AB=√10b/3

We have , <A = 90-<C

Now ,

cos<A =DA/DB

→ cos(90-<C)=(b/3)÷√10b/3=1/√10

→sinC=1/√10

Hence , proved

#CBSE class 10