Physics, asked by varsha84841, 11 months ago

it's pyhsics and the option is c 35​

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Answered by mohan1508
0

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Answered by ShivamKashyap08
10

Answer:

  • Number of bullets (n) Fired per second is 36.

Given:

  1. Mass of Bullet (m) = 5 grams.
  2. Average Force (F) = 180 N.
  3. Velocity of bullet (v) = 1000 m/s.

Explanation:

\rule{300}{1.5}

From the Formula we have,

\large\bigstar \: {\boxed{\tt F = n \Bigg[\dfrac{\Delta P}{\Delta t}\Bigg]}}

\bold{Here}\begin{cases}\text{n Denotes Number of Bullets} \\ \Delta P \text{ Denotes Momentum} \\ \Delta t \text{ Denotes Time taken}\end{cases}

Note:-

  • Here we took n before rate of change in momentum because Many bullets are fired per second.

Now,

\large{\boxed{\tt F = n \Bigg[\dfrac{\Delta P}{\Delta t}\Bigg]}}

Substituting the values,

\large{\tt \longmapsto 180 = n \times \dfrac{mv}{\Delta t}}

∵ [ΔP = mv]

\large{\tt \longmapsto 180 = n \times \dfrac{5 \: g \times 1000 \: m/s}{\Delta t}}

We need to Convert grams into Kilograms.

∵ [1 gram = 10⁻³ Kg]

\large{\tt \longmapsto 180 = n \times \dfrac{5 \times 10^{-3} \: Kg \times 1000 \: m/s}{\Delta t}}

\large{\tt \longmapsto 180 = n \times \dfrac{5 \times 10^{-3} \times 1000}{\Delta t}}

\large{\tt \longmapsto 180 = n \times \dfrac{5 \times 10^{-3} \times 10^3}{\Delta t}}

\large{\tt \longmapsto 180 = n \times \dfrac{5 \times \cancel{10^{-3}} \times \cancel{10^3}}{\Delta t}}

\large{\tt \longmapsto 180 = n \times \dfrac{5 \times 1}{\Delta t}}

\large{\tt \longmapsto 180 = n \times \dfrac{5}{\Delta t}}

Since We need to Find Bullets Fired per Second. Then the Time taken I.e. Δt = 1 second.

\large{\tt \longmapsto 180 = n \times \dfrac{5}{1}}

\large{\tt \longmapsto 180 = 5 \times n}

\large{\tt \longmapsto n = \dfrac{180}{5}}

\large{\tt \longmapsto n = \cancel{\dfrac{180}{5}}}

\large\longmapsto{\underline{\boxed{\red{\tt n = 36 \: Bullets}}}}

Number of bullets (n) Fired per second is 36 Bullets.

\rule{300}{1.5}

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