Question

it's two molecules A and B having mass 100kg and 64kg and rate of diffusion of A is 12*10^-3 , then what will be the rate of diffusion of B​

Answer 1

$\huge\underline{\underline{\bf \green{Question-}}}$

Two molecules A and B having mass 100kg and 64kg and rate of diffusion of A is ${\sf 12×10^{-3}}$ , then what will be the rate of diffusion of B

$\huge\underline{\underline{\bf \green{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Mass of A ${\sf (m_1)}$ = 100 kg
• Mass of B ${\sf (m_2)}$ = 64 kg
• Rate of diffusion of A ${\sf (v_A)=12×10^{-3}}$

$\large\underline{\underline{\sf To\:Find:}}$

• Rate of diffusion of B $]{\sf (v_B)}$

✪$\large{\boxed{\bf \blue{Rate\:of\: diffusion\;\:\:\alpha\:\:\:\dfrac{1}{\sqrt{mass}} }}}$

$\implies{\sf \dfrac{v_A}{v_B}=\sqrt{\dfrac{64}{100}}}$

$\implies{\sf \dfrac{12×10^{-3}}{v_B}=\dfrac{8}{10}}$

$\implies{\sf v_B = \dfrac{12×10^{-3}×10}{8} }$

$\implies{\sf v_B = \dfrac{12×10^{-2}}{8}}$

$\implies{\bf \red{ v_B = 1.5×10^{-2}}}$

$\huge\underline{\underline{\bf \green{Answer-}}}$

Rate of diffusion of gas B is ${\bf \red{v_B = 1.5×10^{-2}}}$

Answer 2

Answer:

rate of diffusion is 1.5×10^-2