Question

It's urgent answer it ​

Answer 1

I hope its useful. pls give me brainlist answer and thanks

Answer 2

$here \: \: p(x) = x {}^{3} - ax {}^{2} +6x - a \\ is \: divided \: by \: x - a \: \\ equate \: x - a = 0 \\ so \: x \: = a \\ \\ substituting \: value \: of \: x \: in \: polynomial \\ p(a) = a {}^{3} - (a)a {}^{2} + 6a - a \\ = a {}^{3} - a {}^{3} + 6a - a \\ = 5a \:$

Mark as brainliest ! ( used remainder theorem )