Question

it's urgent
please help me guy's
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Answer 1

Answer:

Let x= 1

Let p(x)= x³-23x²+142x-120

p(1)= 1³- 23(1²)+142(1)-120

p(1)=1-23+142-120

p(1)= -22+22

p(1)= 0

Therefore, x=1 is a zero of the polynomial.

(x-1) is a factor of the polynomial.

Dividing p(x) by x-1, we get a quotient x²-22x+120 and remainder 0

Now,

p(x)= (x-1)(x²-22x+120)

By splitting the middle term method, we get:

p(x)= (x-1)(x²-12x-10x+120)

p(x)= (x-1)× [x(x-12)-10(x-12)]

p(x)= (x-1)(x-12)(x-10)

This is the factorised form of the cubic polynomial.

I hope this helps you.