Question

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Chapter: Ellipse

Answer 1

Answer:

Step-by-step explanation:

y=mx+a2m2+b2−−−−−−−−√

y−mx=a2m2+b2−−−−−−−−√------(1)

Equation of perpendicular line (1) and passes through (±ae,0) is

my+x=±ae-----(2)

The locus of point of intersection of the line given by equation (1) & (2) can be obtained by eliminating m between them.

Squaring & adding (1) & (2) we get

y2(1+m2)+x2(1+m2)=a2m2+b2+a2e2

(1+m2)(x2+y2)=a2(m2+1)

x2+y2=a2

Hence (a) is the correct answer.