Question

it's urgent plzzz. solve both questions

Answer 1

4___________
Given,
h(x) = xf(x)
differentiate with respect to x
h'(x) = f(x) + xf'(x)
Put x = 0
h'(0) = f(0) + 0.f'(0)
here,
f(0) = -2 and f'(0) = 3 put it
h'(0) = -2 + 0× 3 = -2
h'(0) = -2

5___________
y = log{ logx base 7 }
7^y = logx
now differentiate with respect to x
7^y.log7.dy/dx = 1/x
dy/dx = 1/log7.7^y.x
= 1/x . 1/log7.1/ 7^log{logx base 7 }
= 1/x .1/log7. 1/logx