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HELLO DEAR,
ax/b - by/a = a+b ----------- (1)
ax - by = 2ab -------------(2)
By dividing the second equation by 'a'
ax/b - by/a = a+b ----------- (1)
x - by/a = 2b -------------(2)
Subtracting equation (2) from equation (1)
(ax/b - x) = (a - b)
Bx(a/b - 1) = (a - b)
x/b (a - b) = (a - b)
x/b = 1
X = b.
NOW PUT THE VALUE OF "X" IN EQUATION (2)
WE GET,
b -bY/a =2b
(ab -by)=2b
b(a-y) =2b
a-y=2
y=(a-2)
I HOPE ITS HELP YOU DEAR,
THANKS
ax/b - by/a = a+b ----------- (1)
ax - by = 2ab -------------(2)
By dividing the second equation by 'a'
ax/b - by/a = a+b ----------- (1)
x - by/a = 2b -------------(2)
Subtracting equation (2) from equation (1)
(ax/b - x) = (a - b)
Bx(a/b - 1) = (a - b)
x/b (a - b) = (a - b)
x/b = 1
X = b.
NOW PUT THE VALUE OF "X" IN EQUATION (2)
WE GET,
b -bY/a =2b
(ab -by)=2b
b(a-y) =2b
a-y=2
y=(a-2)
I HOPE ITS HELP YOU DEAR,
THANKS
rohitkumargupta:
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