It's very urgent please solve this and make sure that do in copy and attach it please
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Ok its very easy
Step-by-step explanation:
Given: ABC is an isosceles triangle
BD is perpendicular to AC
D is the midpoint of AC
AB=BC
To Prove: ∆ABD=~ ∆CBD
Proof: In ∆ ABD and ∆CBD
AB=BC ( Given)
BD=BD ( Common)
Angle BAD= Angle BCD ( Opposite angles of
equal sides are equal)
Therefore,
∆ABD =~ ∆CBD
Hence Proved
Please Mark me the brainliest
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