it's Zeros of x square + (A + 1 )X + B are 2 and -3 then find a and b
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Answered by
3
It will definitely help you
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mathupto12:
follow this method
that method is suitable to those who are above the 10th standard
ab kuch
kya?
there is a little problem - a-1=-1 so a=0 sorry for inconvenience
i added u as a brainliest for this question
okk thanx
baaki sb theek h
no problem at all
you will learn that thing in 10th standard
Answered by
3
Hey.....!!! Here is ur answer.....☺️☺️☺️
Here.... Given that,
The Polynomial equation is
x²+(A+1)x+B ..................(1)
And the zeroes of this equation are 2 and -3 then we know that when we will put x= 2,-3 then the solution of this equation will be 0.
Now on putting x = 2 in equation (1)
(2)²+(A+1)2+B=0
=>4+2A+2+B=0
=>2A+B=–6...........(2)
and on putting x=–3 in equation (1)
(–3)²+(A+1)(–3)+B=0
=>9–3A–3+B=0
=>–3A+B=–6.............(3)
On solving equation (2) & (3).....
2A+B=–6......(2)
–3A+B=–6....(3)
A=0 and B=–6
then we have to find sum of A and B
A+B = 0+(–6)=–6 <<<<<<<<<Ans.
I hope this may help you.......✌️✌️✌️
Here.... Given that,
The Polynomial equation is
x²+(A+1)x+B ..................(1)
And the zeroes of this equation are 2 and -3 then we know that when we will put x= 2,-3 then the solution of this equation will be 0.
Now on putting x = 2 in equation (1)
(2)²+(A+1)2+B=0
=>4+2A+2+B=0
=>2A+B=–6...........(2)
and on putting x=–3 in equation (1)
(–3)²+(A+1)(–3)+B=0
=>9–3A–3+B=0
=>–3A+B=–6.............(3)
On solving equation (2) & (3).....
2A+B=–6......(2)
–3A+B=–6....(3)
A=0 and B=–6
then we have to find sum of A and B
A+B = 0+(–6)=–6 <<<<<<<<<Ans.
I hope this may help you.......✌️✌️✌️
ok
why
i added him as a brainliest that's why ?
okk no problem thanks bbye
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