Question

it sin+cos =p and sec+ cosc =q ,then q [ p 2_1]=

Answer 1

Answer:

Step-by-step explanation:

sin+cos=p

sec+cosec=q

q(p^2-1)=

let p=q then

p(p^2-1)=p2

Answer 2

Answer:

Step-by-step explanation: putting the given values in equation

(Sec+cosec)×{(sin+cos)^2-1}=2p

(")×{sin^2+cos^2+2sincos-1}="

(1/cos+1/sin)×{1+2sincos-1}="

Sin+cos/sincos×2sincos="

2×(sin+cos)="

2×(p)="

2p=2p hence proved

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